This is a relatively simple unit, so there aren't too many notes. Basically
Strong acids dissociate to produce H+ ions
Strong bases dissociate to produce OH- ions
However, when strong acids and strong bases mix you get HOH and ionic salt
And since you also know that pH is the measure of H ions present in a solution, you also probably know that pOH would be the measure of OH ions in a solution.
Thus
pH = -log[ H+ ]
pOH = -log [ OH- ]
So here's an example to test you knowledge of the new concept while still incorporating past knowledge.
If .100 L of .40M of HNO3 is added to .300L of .20M of NaOH
First find the limiting reactant
0.1 x (.40mol)/(1L) x 1/1 x (1L)/(.20mol) = .2 L of NaOH is needed
(since you have .300 L of NaOH) HNO3 is the Limiting Reactant
Then find how much NaOH will be left over.
So you find how much NaOH you use, and how much HNO3 you use.
(.3L) x (.2mol)/(1L) = .06 mol of NaOH used
(.1L) x (.4mol)/(1L) = .04 mol of HNO3 used
You then subtract the amount of NaOH used from the amount of HNO3 used
.06-.04 = .02 mol of excess HNO3
Next find the pH
pH = -log [ H+ ]
= -log(.02)
pH = 1.7 (there are no units)
Not too difficult, right? Now if you can do a question like that then you fully understand Acid-Base reactions.
And just make sure you remember your significant digits and decimal points
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